A Level Physics Practice Exam

To determine the energy of an emitted photon from its wavelength, the relationship between energy (E) and wavelength (λ) is described by the equation:

E = (h * c) / λ

where:

- E is the energy of the photon,

- h is Planck's constant, approximately 6.63 × 10^-34 J·s,

- c is the speed of light, approximately 3 × 10^8 m/s,

- λ is the wavelength of the emitted photon.

When wavelength is provided, you can substitute it into the equation using the constants mentioned, allowing you to solve for the energy.

In this case, if you plug in the appropriate values for Planck's constant, the speed of light, and the specific wavelength you are analyzing, you arrive at the value of 9.92 × 10^-19 J for the energy of the photon.

This calculation demonstrates how the energy of a photon is inversely proportional to its wavelength: shorter wavelengths correspond to higher energy photons, whereas longer wavelengths correlate with lower energy photons. Thus, the choice of 9.92 × 10^-19 J accurately reflects the calculated energy based on the principles of photonic energy relations.