A Level Physics Practice Exam

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Question: 1 / 400

If the least distance between two points of a wave with a phase difference of π/3 radians is 0.050 m, what is the speed of the wave if its frequency is 500 Hz?

75 m/s

100 m/s

150 m/s

To solve this question, we start with the concept of phase difference and wave speed. The phase difference $ \Delta \phi $ between two points on a wave is related to the distance $ \Delta x $ between them and the wavelength $ \lambda $ through the following relationship:

\Delta \phi = \frac{2\pi}{\lambda} \Delta x

In this case, the phase difference is given as $ \frac{\pi}{3} $ radians and the least distance between two points is $ 0.050 $ m. Plugging the values into the equation:

\frac{\pi}{3} = \frac{2\pi}{\lambda} \times 0.050

We can rearrange this to find the wavelength $ \lambda $:

\lambda = \frac{2\pi \times 0.050}{\frac{\pi}{3}} = 2 \times 0.050 \times 3 = 0.300 \text{ m}

Now that we have the wavelength, we can calculate the speed $ v $ of the wave using the formula that relates speed, frequency, and

A Level Physics Practice Exam

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